numpy.allclose () in Python

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If the following equation is elementwise True, then allclose returns True.
` absolute (arr1 - arr2) & lt; = (atol + rtol * absolute (arr2)) `
Since the above equation is not symmetric in arr1 and arr2, in some rare cases allclose (arr1, arr2) may differ from allclose (arr2, arr1).

Syntax: numpy.allclose (arr1, arr2, rtol, atol, equal_nan = False)

Parameters:
arr1: [array_like] Input 1st array.
arr2: [array_like] Input 2nd array.
rtol: [float] The relative tolerance parameter.
atol: [float] The absolute tolerance parameter.
equal_nan: [bool] Whether to compare NaN’s as equal. If True, NaN’s in arr1 will be considered equal to NaN’s in arr2 in the output array.

Return: [bool] Returns True if the two arrays are equal within the given tolerance , otherwise it returns False.

Code # 1:

` `

 ` # Python program, explaining ` ` # allclose () function ` ` import ` ` numpy as geek ` ` ` ` # input arrays ` ` in_arr1 ` ` = ` ` geek.array ([` ` 5e5 ` `, ` ` 1e ` ` - ` ` 7 ` `, ` ` 4.000004e6 ` `]) ` ` print ` ` (` ` "1st Input array:" ` `, in_arr1) ` ` in_arr2 ` ` = ` ` geek.array ([` ` 5.00001e5 ` `, ` ` 1e ` ` - ` ` 7 ` `, ` ` 4e6 ` `]) ` ` print ` ` (` ` "2nd Input array:" ` `, in_arr2) ` ` # setting absolute and relative tolerance ` ` rtol ` ` = ` ` 1e ` ` - ` ` 05 ` ` atol ` ` = ` ` 1e ` ` - ` ` 08 ` ` res ` ` = ` ` geek.allclose (in_arr1, in_arr2, rtol, atol) ` ` print ` ` (` `" Are the two arrays are equal within the tolerance: "` `, res) `

` ` Exit:

` 1st Input array: [5.00000000e + 05 1.00000000e-07 4.00000400e + 06] 2nd Input array: [5.00001000e + 05 1.00000000e-07 4.00000000e + 06] Are the two arrays are equal within the tolerance: True `

Code # 2:

 ` # Python program explaining ` ` # allclose () function ` ` import ` ` numpy as geek ` ` # input arrays ` ` in_arr1 ` ` = ` ` geek.array ([` ` 5e5 ` `, ` ` 1e ` ` - ` ` 7 ` `, ` ` 4.000004e6 ` `]) ` ` print ` ` (` ` "1st Input array:" ` `, in_arr1) ` ` in_arr2 ` ` = ` ` geek.array ([` ` 5.00001e5 ` `, ` ` 1e ` ` - ` ` 7 ` `, ` ` 4e6 ` `]) ` ` print ` ` (` ` "2nd Input array:" ` `, in_arr2) ` ` ` ` # setting absolute and relative tolerance ` ` rtol ` ` = ` ` 1e ` ` - ` ` 06 ` ` atol ` ` = ` ` 1e ` ` - ` ` 09 ` ` res ` ` = ` ` geek.allclose (in_arr1, in_arr2, rtol, atol) ` ` print ` ` (` `" Are the two arrays are equal within the tolerance: "` `, res) `

Exit:

` 1st Input array: [5000000.0, 1e-07, 40000004.0] 2nd Input array: [5000001.0, 1e-07, 40000000.0] Are the two arrays are equal within the tolerance: True `

Code # 3:

 ` # Python program explaining ` ` # allclose () function ` ` import ` ` numpy as geek ` ` # input arrays ` ` i n_arr1 ` ` = ` ` geek.array ([` ` 5e5 ` `, ` ` 1e ` ` - ` ` 7 ` `, geek.nan]) ` ` print ` ` (` ` "1st Input array:" ` `, in_arr1) ` ` in_arr2 ` ` = ` ` geek.array ([ ` ` 5e5 ` `, ` ` 1e ` ` - ` ` 7 ` `, geek.nan]) ` ` print ` ` (` `" 2nd Input array: "` `, in_arr2) ` ` # setting absolute and relative tolerance ` ` rtol ` ` = ` ` 1e ` ` - ` ` 06 ` ` atol ` ` = ` ` 1e ` ` - ` ` 09 ` ` ` ` res ` ` = ` ` geek.allclose (in_arr1, in_arr2, rtol, atol) ` ` print ` ` (` ` "Are the two arrays are equal within the tolerance:" ` `, res) `

Exit:

` 1st Input array: [500000.0, 1e-07, nan] 2nd Input array: [500000.0, 1e-07, nan] Are the two arrays are equal within the tolerance: False `

Code # 4:

` `

` # Python program explaining # allclose () function import numpy as geek # input arrays in_arr1 = geek.array ([ 5e5 , 1e - 7 , geek.nan]) print ( "1st Input array:" , in_arr1) in_arr2 = geek.array ([ 5e5 , 1e - 7 , geek.nan]) print ( " 2nd Input array: " , in_arr2) # setting absolute and relative tolerance rtol = 1e - 06 atol = 1e - 09 res = geek.all close (in_arr1, in_arr2, rtol, atol, equal_nan = True ) print ( " Are the two arrays are equal within the tolerance: " , res) `

` ` Output :

` 1st Input array: [500000.0, 1e-07, nan] 2nd Input array: [500000.0, 1e-07, nan] Are the two arrays are equal within the tolerance: True `

numpy.allclose () in Python absolute: Questions

How to get an absolute file path in Python

By izb

Given a path such as `"mydir/myfile.txt"`, how do I find the file"s absolute path relative to the current working directory in Python? E.g. on Windows, I might end up with:

``````"C:/example/cwd/mydir/myfile.txt"
``````
877

``````>>> import os
>>> os.path.abspath("mydir/myfile.txt")
"C:/example/cwd/mydir/myfile.txt"
``````

Also works if it is already an absolute path:

``````>>> import os
>>> os.path.abspath("C:/example/cwd/mydir/myfile.txt")
"C:/example/cwd/mydir/myfile.txt"
``````

numpy.allclose () in Python absolute: Questions

How to check if a path is absolute path or relative path in a cross-platform way with Python?

UNIX absolute path starts with "/", whereas Windows starts with alphabet "C:" or "". Does python have a standard function to check if a path is absolute or relative?

175

`os.path.isabs` returns `True` if the path is absolute, `False` if not. The documentation says it works in windows (I can confirm it works in Linux personally).

``````os.path.isabs(my_path)
``````

numpy.allclose () in Python absolute: Questions

How to join absolute and relative urls?

I have two urls:

``````url1 = "http://127.0.0.1/test1/test2/test3/test5.xml"
url2 = "../../test4/test6.xml"
``````

How can I get an absolute url for url2?

139

You should use urlparse.urljoin :

``````>>> import urlparse
>>> urlparse.urljoin(url1, url2)
"http://127.0.0.1/test1/test4/test6.xml"
``````

With Python 3 (where urlparse is renamed to urllib.parse) you could use it as follow:

``````>>> import urllib.parse
>>> urllib.parse.urljoin(url1, url2)
"http://127.0.0.1/test1/test4/test6.xml"
``````

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