If the following equation is elementwise True, then allclose returns True.
absolute (arr1 - arr2) & lt; = (atol + rtol * absolute (arr2))
Since the above equation is not symmetric in arr1 and arr2, in some rare cases allclose (arr1, arr2) may differ from allclose (arr2, arr1).
Syntax: numpy.allclose (arr1, arr2, rtol, atol, equal_nan = False)
Parameters:
arr1: [array_like] Input 1st array.
arr2: [array_like] Input 2nd array.
rtol: [float] The relative tolerance parameter.
atol: [float] The absolute tolerance parameter.
equal_nan: [bool] Whether to compare NaN’s as equal. If True, NaN’s in arr1 will be considered equal to NaN’s in arr2 in the output array.Return: [bool] Returns True if the two arrays are equal within the given tolerance , otherwise it returns False.
Code # 1:
Exit:
# Python program, explaining
# allclose () function import numpy as geek
# input arrays in_arr1 = geek.array ([ 5e5 , 1e - 7 , 4.000004e6 ]) print ( "1st Input array:" , in_arr1) in_arr2 = geek.array ([ 5.00001e5 , 1e - 7 , 4e6 ]) print ( "2nd Input array:" , in_arr2)
# setting absolute and relative tolerance rtol = 1e - 05 atol = 1e - 08 res = geek.allclose (in_arr1, in_arr2, rtol, atol) print ( " Are the two arrays are equal within the tolerance: " , res)
1st Input array: [5.00000000e + 05 1.00000000e-07 4.00000400e + 06] 2nd Input array: [5.00001000e + 05 1.00000000e-07 4.00000000e + 06] Are the two arrays are equal within the tolerance: True
Code # 2:
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Exit:
1st Input array: [5000000.0, 1e-07, 40000004.0] 2nd Input array: [5000001.0, 1e-07, 40000000.0] Are the two arrays are equal within the tolerance: True
Code # 3:
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Exit:
1st Input array: [500000.0, 1e-07, nan] 2nd Input array: [500000.0, 1e-07, nan] Are the two arrays are equal within the tolerance: False
Code # 4:
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Output :
1st Input array: [500000.0, 1e-07, nan] 2nd Input array: [500000.0, 1e-07, nan] Are the two arrays are equal within the tolerance: True
numpy.allclose () in Python absolute: Questions
How to get an absolute file path in Python
3 answers
Given a path such as "mydir/myfile.txt", how do I find the file"s absolute path relative to the current working directory in Python? E.g. on Windows, I might end up with:
"C:/example/cwd/mydir/myfile.txt"
Answer #1
>>> import os
>>> os.path.abspath("mydir/myfile.txt")
"C:/example/cwd/mydir/myfile.txt"
Also works if it is already an absolute path:
>>> import os
>>> os.path.abspath("C:/example/cwd/mydir/myfile.txt")
"C:/example/cwd/mydir/myfile.txt"
numpy.allclose () in Python absolute: Questions
How to check if a path is absolute path or relative path in a cross-platform way with Python?
3 answers
UNIX absolute path starts with "/", whereas Windows starts with alphabet "C:" or "". Does python have a standard function to check if a path is absolute or relative?
Answer #1
os.path.isabs returns True if the path is absolute, False if not. The documentation says it works in windows (I can confirm it works in Linux personally).
os.path.isabs(my_path)
numpy.allclose () in Python absolute: Questions
How to join absolute and relative urls?
3 answers
I have two urls:
url1 = "http://127.0.0.1/test1/test2/test3/test5.xml"
url2 = "../../test4/test6.xml"
How can I get an absolute url for url2?
Answer #1
You should use urlparse.urljoin :
>>> import urlparse
>>> urlparse.urljoin(url1, url2)
"http://127.0.0.1/test1/test4/test6.xml"
With Python 3 (where urlparse is renamed to urllib.parse) you could use it as follow:
>>> import urllib.parse
>>> urllib.parse.urljoin(url1, url2)
"http://127.0.0.1/test1/test4/test6.xml"
