NLP | Storing an ordered dictionary in Redis

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class RedisOrderedDict (collections.MutableMapping):

  

  def __ init__ ( self , r, name):

self ._ r = r

self ._name = encode_key (name)

  

def __ iter __ ( self ):

return iter ( self . items ())

 

def __ len __ ( self ):

return self ._r.zcard ( self ._ name)

 

  def __ getitem __ ( self , key):

return self ._ r.zscore ( self . _name, encode_key (key))

 

  def __ setitem __ ( self , key, score):

self ._r.zadd ( self ._ name, encode_key (key), score)

 

def __ delitem __ ( self , key):

self ._ r.zrem ( self ._ name, e ncode_key (key))

 

def keys ( self , start = 0 , end = - 1 ):

# we use zrevrange to sort keys

  # by value instead of

lowest

return self ._ r.zrevrange ( self ._ name, start, end)

  

def values ​​( self , start = 0 , end = - 1 ):

return [v for (k, v) in self . items (start = start, end = end)]

 

def items ( self , start = 0 , end = - 1 ):

  return self ._ r.zrevrange ( self ._ name, start, end, withscores = True )

  

  def get ( self , key, default = 0 ):

return self [key] or default

 

def iteritems ( self ):

return iter ( self )

 

def clear ( self ):

  self ._ r.delete ( self ._ name)

Code: Create a RedisOrderedDict instance by passing a Redis connection and unique name

Exit :

 0 5.2000000000000002 1 [(b`bar`, 5.2)] 

Most of the code might look similar to RedisHashMap, which is to be expected since they both extend collections . The main difference is that RedisOrderedSet orders keys by floating point values, and therefore is not suitable for arbitrary storage of key values ​​such as RedisHashMap
Sketches explaining each key method and how they work with Redis:

  • __len __ (): the zcard command is used to get the number of items in an ordered set.
  • __getitem __ (): uses the zscore command to get the score for a key and returns 0 if the key does not exist.
  • __ setitem __ (): this command uses the zadd command to add a key to the ordered set with a given score, or update the score if the key already exists.
  • __delitem __ (): The zrem command is used to remove a key from the ordered set.
  • keys (): The zrevrange command is used to get all the keys in the ordered set sorted by the highest score. To get a snippet of ordered keys more efficiently requires two optional keyword arguments, start and end.

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NLP | Storing an ordered dictionary in Redis __del__: Questions

How can I make a time delay in Python?

5 answers

I would like to know how to put a time delay in a Python script.

2973

Answer #1

import time
time.sleep(5)   # Delays for 5 seconds. You can also use a float value.

Here is another example where something is run approximately once a minute:

import time
while True:
    print("This prints once a minute.")
    time.sleep(60) # Delay for 1 minute (60 seconds).

2973

Answer #2

You can use the sleep() function in the time module. It can take a float argument for sub-second resolution.

from time import sleep
sleep(0.1) # Time in seconds

NLP | Storing an ordered dictionary in Redis __del__: Questions

How to delete a file or folder in Python?

5 answers

How do I delete a file or folder in Python?

2639

Answer #1


Path objects from the Python 3.4+ pathlib module also expose these instance methods:

2639

Answer #2


Path objects from the Python 3.4+ pathlib module also expose these instance methods:

2639

Answer #3

Python syntax to delete a file

import os
os.remove("/tmp/<file_name>.txt")

Or

import os
os.unlink("/tmp/<file_name>.txt")

Or

pathlib Library for Python version >= 3.4

file_to_rem = pathlib.Path("/tmp/<file_name>.txt")
file_to_rem.unlink()

Path.unlink(missing_ok=False)

Unlink method used to remove the file or the symbolik link.

If missing_ok is false (the default), FileNotFoundError is raised if the path does not exist.
If missing_ok is true, FileNotFoundError exceptions will be ignored (same behavior as the POSIX rm -f command).
Changed in version 3.8: The missing_ok parameter was added.

Best practice

  1. First, check whether the file or folder exists or not then only delete that file. This can be achieved in two ways :
    a. os.path.isfile("/path/to/file")
    b. Use exception handling.

EXAMPLE for os.path.isfile

#!/usr/bin/python
import os
myfile="/tmp/foo.txt"

## If file exists, delete it ##
if os.path.isfile(myfile):
    os.remove(myfile)
else:    ## Show an error ##
    print("Error: %s file not found" % myfile)

Exception Handling

#!/usr/bin/python
import os

## Get input ##
myfile= raw_input("Enter file name to delete: ")

## Try to delete the file ##
try:
    os.remove(myfile)
except OSError as e:  ## if failed, report it back to the user ##
    print ("Error: %s - %s." % (e.filename, e.strerror))

RESPECTIVE OUTPUT

Enter file name to delete : demo.txt
Error: demo.txt - No such file or directory.

Enter file name to delete : rrr.txt
Error: rrr.txt - Operation not permitted.

Enter file name to delete : foo.txt

Python syntax to delete a folder

shutil.rmtree()

Example for shutil.rmtree()

#!/usr/bin/python
import os
import sys
import shutil

# Get directory name
mydir= raw_input("Enter directory name: ")

## Try to remove tree; if failed show an error using try...except on screen
try:
    shutil.rmtree(mydir)
except OSError as e:
    print ("Error: %s - %s." % (e.filename, e.strerror))

Is there a simple way to delete a list element by value?

5 answers

I want to remove a value from a list if it exists in the list (which it may not).

a = [1, 2, 3, 4]
b = a.index(6)

del a[b]
print(a)

The above case (in which it does not exist) shows the following error:

Traceback (most recent call last):
  File "D:zjm_codea.py", line 6, in <module>
    b = a.index(6)
ValueError: list.index(x): x not in list

So I have to do this:

a = [1, 2, 3, 4]

try:
    b = a.index(6)
    del a[b]
except:
    pass

print(a)

But is there not a simpler way to do this?

1055

Answer #1

To remove an element"s first occurrence in a list, simply use list.remove:

>>> a = ["a", "b", "c", "d"]
>>> a.remove("b")
>>> print(a)
["a", "c", "d"]

Mind that it does not remove all occurrences of your element. Use a list comprehension for that.

>>> a = [10, 20, 30, 40, 20, 30, 40, 20, 70, 20]
>>> a = [x for x in a if x != 20]
>>> print(a)
[10, 30, 40, 30, 40, 70]

We hope this article has helped you to resolve the problem. Apart from NLP | Storing an ordered dictionary in Redis, check other __del__-related topics.

Want to excel in Python? See our review of the best Python online courses 2023. If you are interested in Data Science, check also how to learn programming in R.

By the way, this material is also available in other languages:



Schneider Lehnman

Milan | 2023-04-01

Simply put and clear. Thank you for sharing. NLP | Storing an ordered dictionary in Redis and other issues with dis Python module was always my weak point 😁. Checked yesterday, it works!

Anna Emmerson

Berlin | 2023-04-01

imp Python module is always a bit confusing 😭 NLP | Storing an ordered dictionary in Redis is not the only problem I encountered. Will get back tomorrow with feedback

Julia Zelotti

Prague | 2023-04-01

Maybe there are another answers? What NLP | Storing an ordered dictionary in Redis exactly means?. Will use it in my bachelor thesis

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from redis import Redis

from rediscollections import RedisOrderedDict

 

r = Redis ()

rod = RedisOrderedDict (r, `test` )

rod.get ( ` bar` )

  

rod [ `bar` ] = 5.2

print (rod [ `bar` ])

 

print ( len (rod))

 

print (rod.items ()) 

 
rod.clear ()