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Examples:
Input: arr = [[1,2,3,4], [8,7,3,2], [9,2,6,3], [5, 1,2,3]] Output: Common Elements = [2,3]
We can quickly solve this problem in python with the intersection_update () Set () data structures .
How does intersection_update () work?
Suppose we have two sets A and B, then operation A.intersection_update (B) updates set A with common elements in sets A and B. For example, A = set ([1,2,3]) and B = set ([4,2,3]) now after accepting A.intersection_update (B) , the value of set A will be [2,3]. Syntax anySet.intersection_update (iterable) .

Output:
Common Elements = [2,3]
This article is courtesy of Shashank Mishra (Gullu) . If you are as Python.Engineering and would like to contribute, you can also write an article using contribute.python.engineering or by posting an article contribute @ python.engineering. See my article appearing on the Python.Engineering homepage and help other geeks.
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Rome  20221210
Simply put and clear. Thank you for sharing. intersection_update () in Python for finding common elements in n arrays and other issues with File handling was always my weak point 😁. Will use it in my bachelor thesis
Munchen  20221210
Arrays is always a bit confusing 😭 intersection_update () in Python for finding common elements in n arrays is not the only problem I encountered. I am just not quite sure it is the best method
Munchen  20221210
Maybe there are another answers? What intersection_update () in Python for finding common elements in n arrays exactly means?. Checked yesterday, it works!