HTML Tag For Javascript

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Understanding basic HTML tags is the fundamental skill in web development. If a website is a house, each HTML tag is like a shaping brick. Just like you can’t figure out how to build a house without understanding how to build a structure, you can’t figure out how to build good websites without understanding HTML.

With web development being one of the top high tech jobs of 2019 , proficiency in basic HTML tags is a great place for learning from.

What are HTML tags?

HTML code displayed on a computer.

you are reading this article on a website Have you ever wondered how the computer knows what. to display the content and how to display it? is it made a bold, italicized text and some contain a link to another web page?

Part of the answer are HTML tags. Once upon a time, HTML was the bulk of the code on the Internet. Although that has changed, HTML is still an important part of getting content on the web.

HTML is a markup language. Once a person has written the content, they will have to tag it with HTML to do things like distinguish title from paragraphs. Most of this is done by placing tags in the content.

What are basic HTML tags ?

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An HTML tag is a special keyword enclosed in brackets, such as:. they come though MPRE in pairs, with an initial and final label. The difference is that the end tags have an additional slash inside the parentheses:

The first tag is the start and the second label is the end.

Here are 10 HTML tags common that every web developer should know and which are especially important for those starting with learning HTML .

1.

This is the root element tag. Indicates that everything between these brackets contains HTML code.

2.

This tag distinguishes the page header from the content. This is where you enter the JavaScript code or provide "meta" information on the site.

3. </ title> </strong></h2><p>Have you noticed that the browser tabs contain text that gives you an overview of the site? This text is written as the title of the site with this tag. </p> <h2> 4. <strong> <body> </ body> </strong></h2><p>The body tag specifies the actual content of the site. </p> <h2> <strong> 5. <h1> </h1> </strong></h2><p>is a header tag , which creates a title by expanding the text and fat. There are six header tags: h1, h2, h3, h4, h5, h6, in descending order of size. </p> <h2> 6. <strong> <p></p> </strong></h2><p>This tag indicates that a particular section should be its own paragraph. Browsers generally insert blank spaces between paragraphs, which makes the text easier to read. </p> <h2> 7. <strong> <a> </a> </strong></h2><p>This tag allows you to create a link with its ’href’ attribute, like this: </ p > <p><a href = www.somewebsite.com> Click here </a>. </p> <h2> <strong> 8. <img> </ img> </strong></h2><p>The ’image’ tag is the way you insert images into a web page. </p> <h2> 9. <strong> </strong></h2><p>Multiple division group contained in a single container, which allows you to perform operations such as than applying a distinct style to the content itself <br> </p> <h2> <strong> 10. <span> </span> </strong></h2><p>Span is like a smaller version of div, used for styling or interacting with online content . You can just add a few words to a particular class (<span> Text </span>) which, again , is great for styling and making the content more responsive. </p> </a> </div> <p>This should be more than enough to start building great websites! </p> <iframe frameborder = "0" width = "100%" height = "400px" data-src = "https://repl.it/@careerkarma/HTML-Tags?lite=true" class = "lazyload "src =" data: image / gif; base64, R0lGODlhAQABAAAAACH5BAEKAAEALAAAAAABAAEAAAICTAEAOw == "> </ iframe> <br> <p> 👻 <em>Read also: what is the <a href="/best-laptop-for-engineering-student/">best laptop for engineering students</a> in 2022?</em> </p> <h2>HTML Tag For Javascript exp: Questions</h2> <div class="question-block"> <div class="question-block__tags"> <a class="question-block__tag tag" href="https://python.engineering/cat/wiki/exp/">exp</a> </div> <p class="question-block__title">How do I merge two dictionaries in a single expression (taking union of dictionaries)?</p> <p class="question-block__answers"><span>5</span> answers</p> <div class="question-block__author"> <img class="question-block__author-img" src="img/article-author-img.jpg" alt="Carl Meyer"> <span class="question-block__author-name">By Carl Meyer</span> </div> <p>I have two Python dictionaries, and I want to write a single expression that returns these two dictionaries, merged (i.e. taking the union). The <code>update()</code> method would be what I need, if it returned its result instead of modifying a dictionary in-place.</p> <pre><code>>>> x = {"a": 1, "b": 2} >>> y = {"b": 10, "c": 11} >>> z = x.update(y) >>> print(z) None >>> x {"a": 1, "b": 10, "c": 11} </code></pre> <p>How can I get that final merged dictionary in <code>z</code>, not <code>x</code>?</p> <p>(To be extra-clear, the last-one-wins conflict-handling of <code>dict.update()</code> is what I"m looking for as well.)</p> </div> <div class="answer"> <div class="answer__stars">5839</div> <div class="answer__inner"> <p class="answer__title">Answer #1</p> <div class="answer__content"> <p><blockquote> <h2 id="how-can-i-merge-two-python-dictionaries-in-a-single-expression-uwzk">How can I merge two Python dictionaries in a single expression?</h2> </blockquote> <p>For dictionaries <code>x</code> and <code>y</code>, <code>z</code> becomes a shallowly-merged dictionary with values from <code>y</code> replacing those from <code>x</code>.</p> <ul> <li><p>In Python 3.9.0 or greater (released 17 October 2020): <a href="https://www.python.org/dev/peps/pep-0584/" rel="noreferrer">PEP-584</a>, <a href="https://bugs.python.org/issue36144" rel="noreferrer">discussed here</a>, was implemented and provides the simplest method:</p> <pre class="lang-py prettyprint-override"><code>z = x | y # NOTE: 3.9+ ONLY </code></pre> </li> <li><p>In Python 3.5 or greater:</p> <pre class="lang-py prettyprint-override"><code>z = {**x, **y} </code></pre> </li> <li><p>In Python 2, (or 3.4 or lower) write a function:</p> <pre class="lang-py prettyprint-override"><code>def merge_two_dicts(x, y): z = x.copy() # start with keys and values of x z.update(y) # modifies z with keys and values of y return z </code></pre> <p>and now:</p> <pre class="lang-py prettyprint-override"><code>z = merge_two_dicts(x, y) </code></pre> </li> </ul> <h3 id="explanation-9ysq">Explanation</h3> <p>Say you have two dictionaries and you want to merge them into a new dictionary without altering the original dictionaries:</p> <pre class="lang-py prettyprint-override"><code>x = {"a": 1, "b": 2} y = {"b": 3, "c": 4} </code></pre> <p>The desired result is to get a new dictionary (<code>z</code>) with the values merged, and the second dictionary"s values overwriting those from the first.</p> <pre class="lang-py prettyprint-override"><code>>>> z {"a": 1, "b": 3, "c": 4} </code></pre> <p>A new syntax for this, proposed in <a href="https://www.python.org/dev/peps/pep-0448" rel="noreferrer">PEP 448</a> and <a href="https://mail.python.org/pipermail/python-dev/2015-February/138564.html" rel="noreferrer">available as of Python 3.5</a>, is</p> <pre class="lang-py prettyprint-override"><code>z = {**x, **y} </code></pre> <p>And it is indeed a single expression.</p> <p>Note that we can merge in with literal notation as well:</p> <pre class="lang-py prettyprint-override"><code>z = {**x, "foo": 1, "bar": 2, **y} </code></pre> <p>and now:</p> <pre class="lang-py prettyprint-override"><code>>>> z {"a": 1, "b": 3, "foo": 1, "bar": 2, "c": 4} </code></pre> <p>It is now showing as implemented in the <a href="https://www.python.org/dev/peps/pep-0478/#features-for-3-5" rel="noreferrer">release schedule for 3.5, PEP 478</a>, and it has now made its way into the <a href="https://docs.python.org/dev/whatsnew/3.5.html#pep-448-additional-unpacking-generalizations" rel="noreferrer">What"s New in Python 3.5</a> document.</p> <p>However, since many organizations are still on Python 2, you may wish to do this in a backward-compatible way. The classically Pythonic way, available in Python 2 and Python 3.0-3.4, is to do this as a two-step process:</p> <pre class="lang-py prettyprint-override"><code>z = x.copy() z.update(y) # which returns None since it mutates z </code></pre> <p>In both approaches, <code>y</code> will come second and its values will replace <code>x</code>"s values, thus <code>b</code> will point to <code>3</code> in our final result.</p> <h2 id="not-yet-on-python-3.5-but-want-a-single-expression-zmt4">Not yet on Python 3.5, but want a <em>single expression</em></h2> <p>If you are not yet on Python 3.5 or need to write backward-compatible code, and you want this in a <em>single expression</em>, the most performant while the correct approach is to put it in a function:</p> <pre class="lang-py prettyprint-override"><code>def merge_two_dicts(x, y): """Given two dictionaries, merge them into a new dict as a shallow copy.""" z = x.copy() z.update(y) return z </code></pre> <p>and then you have a single expression:</p> <pre class="lang-py prettyprint-override"><code>z = merge_two_dicts(x, y) </code></pre> <p>You can also make a function to merge an arbitrary number of dictionaries, from zero to a very large number:</p> <pre class="lang-py prettyprint-override"><code>def merge_dicts(*dict_args): """ Given any number of dictionaries, shallow copy and merge into a new dict, precedence goes to key-value pairs in latter dictionaries. """ result = {} for dictionary in dict_args: result.update(dictionary) return result </code></pre> <p>This function will work in Python 2 and 3 for all dictionaries. e.g. given dictionaries <code>a</code> to <code>g</code>:</p> <pre class="lang-py prettyprint-override"><code>z = merge_dicts(a, b, c, d, e, f, g) </code></pre> <p>and key-value pairs in <code>g</code> will take precedence over dictionaries <code>a</code> to <code>f</code>, and so on.</p> <h2 id="critiques-of-other-answers-fxgc">Critiques of Other Answers</h2> <p>Don"t use what you see in the formerly accepted answer:</p> <pre class="lang-py prettyprint-override"><code>z = dict(x.items() + y.items()) </code></pre> <p>In Python 2, you create two lists in memory for each dict, create a third list in memory with length equal to the length of the first two put together, and then discard all three lists to create the dict. <strong>In Python 3, this will fail</strong> because you"re adding two <code>dict_items</code> objects together, not two lists -</p> <pre class="lang-py prettyprint-override"><code>>>> c = dict(a.items() + b.items()) Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: unsupported operand type(s) for +: "dict_items" and "dict_items" </code></pre> <p>and you would have to explicitly create them as lists, e.g. <code>z = dict(list(x.items()) + list(y.items()))</code>. This is a waste of resources and computation power.</p> <p>Similarly, taking the union of <code>items()</code> in Python 3 (<code>viewitems()</code> in Python 2.7) will also fail when values are unhashable objects (like lists, for example). Even if your values are hashable, <strong>since sets are semantically unordered, the behavior is undefined in regards to precedence. So don"t do this:</strong></p> <pre class="lang-py prettyprint-override"><code>>>> c = dict(a.items() | b.items()) </code></pre> <p>This example demonstrates what happens when values are unhashable:</p> <pre class="lang-py prettyprint-override"><code>>>> x = {"a": []} >>> y = {"b": []} >>> dict(x.items() | y.items()) Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: unhashable type: "list" </code></pre> <p>Here"s an example where <code>y</code> should have precedence, but instead the value from <code>x</code> is retained due to the arbitrary order of sets:</p> <pre class="lang-py prettyprint-override"><code>>>> x = {"a": 2} >>> y = {"a": 1} >>> dict(x.items() | y.items()) {"a": 2} </code></pre> <p>Another hack you should not use:</p> <pre class="lang-py prettyprint-override"><code>z = dict(x, **y) </code></pre> <p>This uses the <code>dict</code> constructor and is very fast and memory-efficient (even slightly more so than our two-step process) but unless you know precisely what is happening here (that is, the second dict is being passed as keyword arguments to the dict constructor), it"s difficult to read, it"s not the intended usage, and so it is not Pythonic.</p> <p>Here"s an example of the usage being <a href="https://code.djangoproject.com/attachment/ticket/13357/django-pypy.2.diff" rel="noreferrer">remediated in django</a>.</p> <p>Dictionaries are intended to take hashable keys (e.g. <code>frozenset</code>s or tuples), but <strong>this method fails in Python 3 when keys are not strings.</strong></p> <pre class="lang-py prettyprint-override"><code>>>> c = dict(a, **b) Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: keyword arguments must be strings </code></pre> <p>From the <a href="https://mail.python.org/pipermail/python-dev/2010-April/099459.html" rel="noreferrer">mailing list</a>, Guido van Rossum, the creator of the language, wrote:</p> <blockquote> <p>I am fine with declaring dict({}, **{1:3}) illegal, since after all it is abuse of the ** mechanism.</p> </blockquote> <p>and</p> <blockquote> <p>Apparently dict(x, **y) is going around as "cool hack" for "call x.update(y) and return x". Personally, I find it more despicable than cool.</p> </blockquote> <p>It is my understanding (as well as the understanding of the <a href="https://mail.python.org/pipermail/python-dev/2010-April/099485.html" rel="noreferrer">creator of the language</a>) that the intended usage for <code>dict(**y)</code> is for creating dictionaries for readability purposes, e.g.:</p> <pre class="lang-py prettyprint-override"><code>dict(a=1, b=10, c=11) </code></pre> <p>instead of</p> <pre class="lang-py prettyprint-override"><code>{"a": 1, "b": 10, "c": 11} </code></pre> <h2 id="response-to-comments-zkqe">Response to comments</h2> <blockquote> <p>Despite what Guido says, <code>dict(x, **y)</code> is in line with the dict specification, which btw. works for both Python 2 and 3. The fact that this only works for string keys is a direct consequence of how keyword parameters work and not a short-coming of dict. Nor is using the ** operator in this place an abuse of the mechanism, in fact, ** was designed precisely to pass dictionaries as keywords.</p> </blockquote> <p>Again, it doesn"t work for 3 when keys are not strings. The implicit calling contract is that namespaces take ordinary dictionaries, while users must only pass keyword arguments that are strings. All other callables enforced it. <code>dict</code> broke this consistency in Python 2:</p> <pre><code>>>> foo(**{("a", "b"): None}) Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: foo() keywords must be strings >>> dict(**{("a", "b"): None}) {("a", "b"): None} </code></pre> <p>This inconsistency was bad given other implementations of Python (PyPy, Jython, IronPython). Thus it was fixed in Python 3, as this usage could be a breaking change.</p> <p>I submit to you that it is malicious incompetence to intentionally write code that only works in one version of a language or that only works given certain arbitrary constraints.</p> <p>More comments:</p> <blockquote> <p><code>dict(x.items() + y.items())</code> is still the most readable solution for Python 2. Readability counts.</p> </blockquote> <p>My response: <code>merge_two_dicts(x, y)</code> actually seems much clearer to me, if we"re actually concerned about readability. And it is not forward compatible, as Python 2 is increasingly deprecated.</p> <blockquote> <p><code>{**x, **y}</code> does not seem to handle nested dictionaries. the contents of nested keys are simply overwritten, not merged [...] I ended up being burnt by these answers that do not merge recursively and I was surprised no one mentioned it. In my interpretation of the word "merging" these answers describe "updating one dict with another", and not merging.</p> </blockquote> <p>Yes. I must refer you back to the question, which is asking for a <em>shallow</em> merge of <em><strong>two</strong></em> dictionaries, with the first"s values being overwritten by the second"s - in a single expression.</p> <p>Assuming two dictionaries of dictionaries, one might recursively merge them in a single function, but you should be careful not to modify the dictionaries from either source, and the surest way to avoid that is to make a copy when assigning values. As keys must be hashable and are usually therefore immutable, it is pointless to copy them:</p> <pre class="lang-py prettyprint-override"><code>from copy import deepcopy def dict_of_dicts_merge(x, y): z = {} overlapping_keys = x.keys() & y.keys() for key in overlapping_keys: z[key] = dict_of_dicts_merge(x[key], y[key]) for key in x.keys() - overlapping_keys: z[key] = deepcopy(x[key]) for key in y.keys() - overlapping_keys: z[key] = deepcopy(y[key]) return z </code></pre> <p>Usage:</p> <pre class="lang-py prettyprint-override"><code>>>> x = {"a":{1:{}}, "b": {2:{}}} >>> y = {"b":{10:{}}, "c": {11:{}}} >>> dict_of_dicts_merge(x, y) {"b": {2: {}, 10: {}}, "a": {1: {}}, "c": {11: {}}} </code></pre> <p>Coming up with contingencies for other value types is far beyond the scope of this question, so I will point you at <a href="https://stackoverflow.com/a/24088493/541136">my answer to the canonical question on a "Dictionaries of dictionaries merge"</a>.</p> <h2 id="less-performant-but-correct-ad-hocs-zrgm">Less Performant But Correct Ad-hocs</h2> <p>These approaches are less performant, but they will provide correct behavior. They will be <em>much less</em> performant than <code>copy</code> and <code>update</code> or the new unpacking because they iterate through each key-value pair at a higher level of abstraction, but they <em>do</em> respect the order of precedence (latter dictionaries have precedence)</p> <p>You can also chain the dictionaries manually inside a <a href="https://www.python.org/dev/peps/pep-0274/" rel="noreferrer">dict comprehension</a>:</p> <pre class="lang-py prettyprint-override"><code>{k: v for d in dicts for k, v in d.items()} # iteritems in Python 2.7 </code></pre> <p>or in Python 2.6 (and perhaps as early as 2.4 when generator expressions were introduced):</p> <pre class="lang-py prettyprint-override"><code>dict((k, v) for d in dicts for k, v in d.items()) # iteritems in Python 2 </code></pre> <p><code>itertools.chain</code> will chain the iterators over the key-value pairs in the correct order:</p> <pre class="lang-py prettyprint-override"><code>from itertools import chain z = dict(chain(x.items(), y.items())) # iteritems in Python 2 </code></pre> <h2 id="performance-analysis-c4us">Performance Analysis</h2> <p>I"m only going to do the performance analysis of the usages known to behave correctly. (Self-contained so you can copy and paste yourself.)</p> <pre class="lang-py prettyprint-override"><code>from timeit import repeat from itertools import chain x = dict.fromkeys("abcdefg") y = dict.fromkeys("efghijk") def merge_two_dicts(x, y): z = x.copy() z.update(y) return z min(repeat(lambda: {**x, **y})) min(repeat(lambda: merge_two_dicts(x, y))) min(repeat(lambda: {k: v for d in (x, y) for k, v in d.items()})) min(repeat(lambda: dict(chain(x.items(), y.items())))) min(repeat(lambda: dict(item for d in (x, y) for item in d.items()))) </code></pre> <p>In Python 3.8.1, NixOS:</p> <pre class="lang-py prettyprint-override"><code>>>> min(repeat(lambda: {**x, **y})) 1.0804965235292912 >>> min(repeat(lambda: merge_two_dicts(x, y))) 1.636518670246005 >>> min(repeat(lambda: {k: v for d in (x, y) for k, v in d.items()})) 3.1779992282390594 >>> min(repeat(lambda: dict(chain(x.items(), y.items())))) 2.740647904574871 >>> min(repeat(lambda: dict(item for d in (x, y) for item in d.items()))) 4.266070580109954 </code></pre> <pre class="lang-sh prettyprint-override"><code>$ uname -a Linux nixos 4.19.113 #1-NixOS SMP Wed Mar 25 07:06:15 UTC 2020 x86_64 GNU/Linux </code></pre> <h2 id="resources-on-dictionaries-e74r">Resources on Dictionaries</h2> <ul> <li><a href="https://stackoverflow.com/questions/327311/how-are-pythons-built-in-dictionaries-implemented/44509302#44509302">My explanation of Python"s <strong>dictionary implementation</strong>, updated for 3.6.</a></li> <li><a href="https://stackoverflow.com/questions/1024847/add-new-keys-to-a-dictionary/27208535#27208535">Answer on how to add new keys to a dictionary</a></li> <li><a href="https://stackoverflow.com/questions/209840/map-two-lists-into-a-dictionary-in-python/33737067#33737067">Mapping two lists into a dictionary</a></li> <li><a href="https://docs.python.org/3/tutorial/datastructures.html#dictionaries" rel="noreferrer">The official Python docs on dictionaries</a></li> <li><a href="https://www.youtube.com/watch?v=66P5FMkWoVU" rel="noreferrer">The Dictionary Even Mightier</a> - talk by Brandon Rhodes at Pycon 2017</li> <li><a href="https://www.youtube.com/watch?v=npw4s1QTmPg" rel="noreferrer">Modern Python Dictionaries, A Confluence of Great Ideas</a> - talk by Raymond Hettinger at Pycon 2017</li> </ul></p> </div> </div> </div> <div class="answer"> <div class="answer__stars">5839</div> <div class="answer__inner"> <p class="answer__title">Answer #2</p> <div class="answer__content"> <p><p>In your case, what you can do is:</p> <pre class="lang-py prettyprint-override"><code>z = dict(list(x.items()) + list(y.items())) </code></pre> <p>This will, as you want it, put the final dict in <code>z</code>, and make the value for key <code>b</code> be properly overridden by the second (<code>y</code>) dict"s value:</p> <pre class="lang-py prettyprint-override"><code>>>> x = {"a":1, "b": 2} >>> y = {"b":10, "c": 11} >>> z = dict(list(x.items()) + list(y.items())) >>> z {"a": 1, "c": 11, "b": 10} </code></pre> <p>If you use Python 2, you can even remove the <code>list()</code> calls. To create z:</p> <pre class="lang-py prettyprint-override"><code>>>> z = dict(x.items() + y.items()) >>> z {"a": 1, "c": 11, "b": 10} </code></pre> <p>If you use Python version 3.9.0a4 or greater, then you can directly use:</p> <pre class="lang-py prettyprint-override"><code>x = {"a":1, "b": 2} y = {"b":10, "c": 11} z = x | y print(z) </code></pre> <pre class="lang-py prettyprint-override"><code>{"a": 1, "c": 11, "b": 10} </code></pre></p> </div> </div> </div> <div class="answer"> <div class="answer__stars">5839</div> <div class="answer__inner"> <p class="answer__title">Answer #3</p> <div class="answer__content"> <p><p>An alternative:</p> <pre><code>z = x.copy() z.update(y) </code></pre></p> </div> </div> </div> <div class="question-block"> <div class="question-block__tags"> <a class="question-block__tag tag" href="https://python.engineering/cat/wiki/insert/">insert</a> </div> <p class="question-block__title">How to insert newlines on argparse help text?</p> <p class="question-block__answers"><span>5</span> answers</p> <p>I"m using <a href="http://docs.python.org/library/argparse.html" rel="noreferrer"><code>argparse</code> in Python 2.7</a> for parsing input options. One of my options is a multiple choice. I want to make a list in its help text, e.g.</p> <pre><code>from argparse import ArgumentParser parser = ArgumentParser(description="test") parser.add_argument("-g", choices=["a", "b", "g", "d", "e"], default="a", help="Some option, where " " a = alpha " " b = beta " " g = gamma " " d = delta " " e = epsilon") parser.parse_args() </code></pre> <p>However, <code>argparse</code> strips all newlines and consecutive spaces. The result looks like</p> <pre> ~/Downloads:52$ python2.7 x.py -h usage: x.py [-h] [-g {a,b,g,d,e}] test optional arguments: -h, --help show this help message and exit -g {a,b,g,d,e} Some option, where a = alpha b = beta g = gamma d = delta e = epsilon </pre> <p>How to insert newlines in the help text?</p> </div> <div class="answer"> <div class="answer__stars">406</div> <div class="answer__inner"> <p class="answer__title">Answer #1</p> <div class="answer__content"> <p><p>Try using <a href="https://docs.python.org/2/library/argparse.html#formatter-class" rel="noreferrer"><code>RawTextHelpFormatter</code></a>:</p> <pre><code>from argparse import RawTextHelpFormatter parser = ArgumentParser(description="test", formatter_class=RawTextHelpFormatter) </code></pre></p> </div> </div> </div> <div class="question-block"> <div class="question-block__tags"> <a class="question-block__tag tag" href="https://python.engineering/cat/wiki/insert/">insert</a> </div> <p class="question-block__title">Is a Python list guaranteed to have its elements stay in the order they are inserted in?</p> <p class="question-block__answers"><span>5</span> answers</p> <p>If I have the following Python code</p> <pre><code>>>> x = [] >>> x = x + [1] >>> x = x + [2] >>> x = x + [3] >>> x [1, 2, 3] </code></pre> <p>Will <code>x</code> be guaranteed to always be <code>[1,2,3]</code>, or are other orderings of the interim elements possible?</p> </div> <div class="answer"> <div class="answer__stars">366</div> <div class="answer__inner"> <p class="answer__title">Answer #1</p> <div class="answer__content"> <p><p>Yes, the order of elements in a python list is persistent.</p></p> </div> </div> </div> <div class="question-block"> <div class="question-block__tags"> <a class="question-block__tag tag" href="https://python.engineering/cat/wiki/insert/">insert</a> </div> <p class="question-block__title">Inserting image into IPython notebook markdown</p> <p class="question-block__answers"><span>5</span> answers</p> <p>I am starting to depend heavily on the IPython notebook app to develop and document algorithms. It is awesome; but there is something that seems like it should be possible, but I can"t figure out how to do it:</p> <p>I would like to insert a local image into my (local) IPython notebook markdown to aid in documenting an algorithm. I know enough to add something like <code><img src="image.png"></code> to the markdown, but that is about as far as my knowledge goes. I assume I could put the image in the directory represented by 127.0.0.1:8888 (or some subdirectory) to be able to access it, but I can"t figure out where that directory is. (I"m working on a mac.) So, is it possible to do what I"m trying to do without too much trouble?</p> </div> <div class="answer"> <div class="answer__stars">277</div> <div class="answer__inner"> <p class="answer__title">Answer #1</p> <div class="answer__content"> <p><p>Most of the answers given so far go in the wrong direction, suggesting to load additional libraries and use the code instead of markup. In Ipython/Jupyter Notebooks it is very simple. Make sure the cell is indeed in markup and to display a image use:</p> <pre><code>![alt text](imagename.png "Title") </code></pre> <p>Further advantage compared to the other methods proposed is that you can display all common file formats including jpg, png, and gif (animations).</p></p> </div> </div> </div> </div> </div> <div class="article__right"> <div class="hub_ad"> <div id="ezoic-pub-ad-placeholder-106"> <script async src="https://pagead2.googlesyndication.com/pagead/js/adsbygoogle.js?client=ca-pub-9381065361874746" crossorigin="anonymous"></script> <!-- PYE aside NEW --> <ins class="adsbygoogle" style="display:block" data-ad-client="ca-pub-9381065361874746" data-ad-slot="8755532771" data-ad-format="auto" data-full-width-responsive="true"></ins> <script> (adsbygoogle = window.adsbygoogle || []).push({}); </script> </div> </div> <div class="shop-aside shop-aside--mt"> <h2 class="shop-aside__title">Shop</h2> <div class="shop__items shop__items--column"> <div class="shop__item"><a 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