os.path.dirname(__file__) returns empty

| | | | |

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I want to get the path of the current directory under which a .py file is executed.

For example a simple file D: est.py with code:

import os

print os.getcwd()
print os.path.basename(__file__)
print os.path.abspath(__file__)
print os.path.dirname(__file__)

It is weird that the output is:

D:
test.py
D:	est.py
EMPTY

I am expecting the same results from the getcwd() and path.dirname().

Given os.path.abspath = os.path.dirname + os.path.basename, why

os.path.dirname(__file__)

returns empty?

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os.path.dirname(__file__) returns empty basename: Questions

What is the difference between os.path.basename() and os.path.dirname()?

1 answers

What is the difference between os.path.basename() and os.path.dirname()?

I already searched for answers and read some links, but didn"t understand. Can anyone give a simple explanation?

158

Answer #1

Both functions use the os.path.split(path) function to split the pathname path into a pair; (head, tail).

The os.path.dirname(path) function returns the head of the path.

E.g.: The dirname of "/foo/bar/item" is "/foo/bar".

The os.path.basename(path) function returns the tail of the path.

E.g.: The basename of "/foo/bar/item" returns "item"

From: http://docs.python.org/3/library/os.path.html#os.path.basename

We hope this article has helped you to resolve the problem. Apart from os.path.dirname(__file__) returns empty, check other basename-related topics.

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Julia Wu

Vigrinia | 2022-11-28

Maybe there are another answers? What os.path.dirname(__file__) returns empty exactly means?. Will get back tomorrow with feedback

Manuel Porretti

Shanghai | 2022-11-28

Thanks for explaining! I was stuck with os.path.dirname(__file__) returns empty for some hours, finally got it done 🤗. Checked yesterday, it works!

Boris Emmerson

Milan | 2022-11-28

Simply put and clear. Thank you for sharing. os.path.dirname(__file__) returns empty and other issues with exp was always my weak point 😁. Will get back tomorrow with feedback

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