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I need to pass a file path name to a module. How do I build the file path from a directory name, base filename, and a file format string?
The directory may or may not exist at the time of call.
For example:
dir_name="/home/me/dev/my_reports"
base_filename="daily_report"
format = "pdf"
I need to create a string "/home/me/dev/my_reports/daily_report.pdf"
Concatenating the pieces manually doesn"t seem to be a good way. I tried os.path.join
:
join(dir_name,base_filename,format)
but it gives
/home/me/dev/my_reports/daily_report/pdf
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Warsaw | 2023-03-23
Simply put and clear. Thank you for sharing. Build the full path filename in Python and other issues with time Python module was always my weak point 😁. Will use it in my bachelor thesis
Prague | 2023-03-23
Thanks for explaining! I was stuck with Build the full path filename in Python for some hours, finally got it done 🤗. Checked yesterday, it works!
Singapore | 2023-03-23
join is always a bit confusing 😭 Build the full path filename in Python is not the only problem I encountered. Checked yesterday, it works!