Convert Year/Month/Day to Day of Year in Python

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I"m using the datetime module, i.e.:

>>> import datetime
>>> today = datetime.datetime.now()
>>> print(today)
2009-03-06 13:24:58.857946

and I would like to compute the day of year that takes leap years into account. e.g. today (March 6, 2009) is the 65th day of 2009.

I see a two options:

1. Create a number_of_days_in_month = [31, 28, ...] array, decide if it"s a leap year and manually sum up the days.

2. Use datetime.timedelta to make a guess & then binary search for the correct day of the year:

   >>> import datetime
   >>> YEAR = 2009
   >>> DAY_OF_YEAR = 62
   >>> d = datetime.date(YEAR, 1, 1) + datetime.timedelta(DAY_OF_YEAR - 1)
   

These both feel pretty clunky & I have a gut feeling that there"s a more "Pythonic" way of calculating the day of the year. Any ideas/suggestions?

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Convert Year/Month/Day to Day of Year in Python __del__: Questions

import time
time.sleep(5)   # Delays for 5 seconds. You can also use a float value.

import time
while True:
    print("This prints once a minute.")
    time.sleep(60) # Delay for 1 minute (60 seconds).

from time import sleep
sleep(0.1) # Time in seconds

Convert Year/Month/Day to Day of Year in Python __del__: Questions

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