argparse module How to add option without any argument?

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I have created a script using argparse.

The script needs to take a configuration file name as an option, and user can specify whether they need to proceed totally the script or only simulate it.

The args to be passed: ./script -f config_file -s or ./script -f config_file.

It"s ok for the -f config_file part, but It keeps asking me for arguments for the -s which is optionnal and should not be followed by any.

I have tried this:

parser = argparse.ArgumentParser()
parser.add_argument("-f", "--file")
#parser.add_argument("-s", "--simulate", nargs = "0")
args = parser.parse_args()
if args.file:
    config_file = args.file
if args.set_in_prod:
        simulate = True
else:
    pass

With the following errors:

File "/usr/local/lib/python2.6/dist-packages/argparse.py", line 2169, in _get_nargs_pattern
nargs_pattern = "(-*%s-*)" % "-*".join("A" * nargs)
TypeError: can"t multiply sequence by non-int of type "str"

And same errror with "" instead of 0.

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Schneider Nickolson

Massachussetts | 2023-03-22

Simply put and clear. Thank you for sharing. argparse module How to add option without any argument? and other issues with io Python module was always my weak point 😁. I am just not quite sure it is the best method

Javier OConnell

Prague | 2023-03-22

Simply put and clear. Thank you for sharing. argparse module How to add option without any argument? and other issues with code Python module was always my weak point 😁. Checked yesterday, it works!

Xu Ungerschaft

Shanghai | 2023-03-22

I was preparing for my coding interview, thanks for clarifying this - argparse module How to add option without any argument? in Python is not the simplest one. Checked yesterday, it works!

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