How is Python”s List Implemented?

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Is it a linked list, an array? I searched around and only found people guessing. My C knowledge isn"t good enough to look at the source code.

Answer rating: 271

The C code is pretty simple, actually. Expanding one macro and pruning some irrelevant comments, the basic structure is in listobject.h, which defines a list as:

typedef struct {
    PyObject_HEAD
    Py_ssize_t ob_size;

    /* Vector of pointers to list elements.  list[0] is ob_item[0], etc. */
    PyObject **ob_item;

    /* ob_item contains space for "allocated" elements.  The number
     * currently in use is ob_size.
     * Invariants:
     *     0 <= ob_size <= allocated
     *     len(list) == ob_size
     *     ob_item == NULL implies ob_size == allocated == 0
     */
    Py_ssize_t allocated;
} PyListObject;

PyObject_HEAD contains a reference count and a type identifier. So, it"s a vector/array that overallocates. The code for resizing such an array when it"s full is in listobject.c. It doesn"t actually double the array, but grows by allocating

new_allocated = (newsize >> 3) + (newsize < 9 ? 3 : 6);
new_allocated += newsize;

to the capacity each time, where newsize is the requested size (not necessarily allocated + 1 because you can extend by an arbitrary number of elements instead of append"ing them one by one).

See also the Python FAQ.





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