return string with first match Regex

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I want to get the first match of a regex.

In this case, I got a list:

text = "aa33bbb44"
re.findall("d+",text)

["33", "44"]

I could extract the first element of the list:

text = "aa33bbb44"
re.findall("d+",text)[0]

"33"

But that only works if there is at least one match, otherwise I"ll get an error:

text = "aazzzbbb"
re.findall("d+",text)[0]

IndexError: list index out of range

In which case I could define a function:

def return_first_match(text):
    try:
        result = re.findall("d+",text)[0]
    except Exception, IndexError:
        result = ""
    return result

Is there a way of obtaining that result without defining a new function?

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