How to get the parent dir location

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this code is get the templates/blog1/page.html in b.py:

path = os.path.join(os.path.dirname(__file__), os.path.join("templates", "blog1/page.html"))

but i want to get the parent dir location:

aParent
   |--a
   |  |---b.py
   |      |---templates
   |              |--------blog1
   |                         |-------page.html
   |--templates
          |--------blog1
                     |-------page.html

and how to get the aParent location

thanks

updated:

this is right:

dirname=os.path.dirname
path = os.path.join(dirname(dirname(__file__)), os.path.join("templates", "blog1/page.html"))

or

path = os.path.abspath(os.path.join(os.path.dirname(__file__),".."))

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os.path.dirname(__file__) returns empty

2 answers

I want to get the path of the current directory under which a .py file is executed.

For example a simple file D: est.py with code:

import os

print os.getcwd()
print os.path.basename(__file__)
print os.path.abspath(__file__)
print os.path.dirname(__file__)

It is weird that the output is:

D:
test.py
D:	est.py
EMPTY

I am expecting the same results from the getcwd() and path.dirname().

Given os.path.abspath = os.path.dirname + os.path.basename, why

os.path.dirname(__file__)

returns empty?

174

Answer #1

Because os.path.abspath = os.path.dirname + os.path.basename does not hold. we rather have

os.path.dirname(filename) + os.path.basename(filename) == filename

Both dirname() and basename() only split the passed filename into components without taking into account the current directory. If you want to also consider the current directory, you have to do so explicitly.

To get the dirname of the absolute path, use

os.path.dirname(os.path.abspath(__file__))

What is the difference between os.path.basename() and os.path.dirname()?

2 answers

What is the difference between os.path.basename() and os.path.dirname()?

I already searched for answers and read some links, but didn"t understand. Can anyone give a simple explanation?

158

Answer #1

Both functions use the os.path.split(path) function to split the pathname path into a pair; (head, tail).

The os.path.dirname(path) function returns the head of the path.

E.g.: The dirname of "/foo/bar/item" is "/foo/bar".

The os.path.basename(path) function returns the tail of the path.

E.g.: The basename of "/foo/bar/item" returns "item"

From: http://docs.python.org/3/library/os.path.html#os.path.basename

We hope this article has helped you to resolve the problem. Apart from How to get the parent dir location, check other code Python module-related topics.

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Frank Wu

New York | 2023-01-27

Simply put and clear. Thank you for sharing. How to get the parent dir location and other issues with html Python module was always my weak point 😁. Will use it in my bachelor thesis

Oliver Wu

Prague | 2023-01-27

Maybe there are another answers? What How to get the parent dir location exactly means?. Checked yesterday, it works!

Carlo Zelotti

London | 2023-01-27

Maybe there are another answers? What How to get the parent dir location exactly means?. I just hope that will not emerge anymore

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