Displaying better error message than “No JSON object could be decoded”

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Python code to load data from some long complicated JSON file:

with open(filename, "r") as f:
  data = json.loads(f.read())

(note: the best code version should be:

with open(filename, "r") as f:
  data = json.load(f)

but both exhibit similar behavior)

For many types of JSON error (missing delimiters, incorrect backslashes in strings, etc), this prints a nice helpful message containing the line and column number where the JSON error was found.

However, for other types of JSON error (including the classic "using comma on the last item in a list", but also other things like capitalising true/false), Python"s output is just:

Traceback (most recent call last):
  File "myfile.py", line 8, in myfunction
    config = json.loads(f.read())
  File "c:python27libjson\__init__.py", line 326, in loads
    return _default_decoder.decode(s)
  File "c:python27libjsondecoder.py", line 360, in decode
    obj, end = self.raw_decode(s, idx=_w(s, 0).end())
  File "c:python27libjsondecoder.py", line 378, in raw_decode
    raise ValueError("No JSON object could be decoded")
ValueError: No JSON object could be decoded

For that type of ValueError, how do you get Python to tell you where is the error in the JSON file?

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Displaying better error message than "No JSON object could be decoded" __del__: Questions

import time
time.sleep(5)   # Delays for 5 seconds. You can also use a float value.

import time
while True:
    print("This prints once a minute.")
    time.sleep(60) # Delay for 1 minute (60 seconds).

from time import sleep
sleep(0.1) # Time in seconds

Displaying better error message than "No JSON object could be decoded" __del__: Questions

We hope this article has helped you to resolve the problem. Apart from Displaying better error message than “No JSON object could be decoded”, check other __del__-related topics.

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